
In an archtop guitar (or any guitar for that matter - I think. Maybe.) you have a decision to make about the footprint of the bridge as it sits on the arched top of the guitar. Does that contact area make a difference - large, small or none - in the efficacy of energy transfer to the top? I think that inside of a window of possibilities, it does not make much difference at all, and smaller may be better.
1. Consider a traditional tuning fork with a ball on the ends of the handle. You tap the fork and touch the ball to the surface of the bridge and it creates a loud tone. Given a very stiff brittle wood in the bridge - ebony - and a perfectly round steel ball of exceptional hardness, the contact area is infinitesimally small yet the energy transfer is exceptional.
2. A large contact area requires a large bridge, therefore greater mass. To transfer energy the string must excite the mass of the bridge, so a large heavy wooden bridge will dampen the transfer of energy, or simply absorb some energy and not pass it to the top. Every time I've made a bridge heavy (not adding weights, which is a somewhat different thing, but made the actual bridge construction heavy) I lost volume, and making the bridge light increased volume. (I don't really mean "volume" but rather the whole concept of the sound of the guitar, maybe with an emphasis on increase harmonic richness, or shimmer. I don't know a word for that)
3.Transfer of energy between the top and the bridge. Greater surface area reduces the per-unit loading of the interface, smaller surface area increases the per-unit loading. I believe that if you stay within the elastic limits of the material, so that both the pre-load on the bridge (the downforce from the string break angle) and the added load of transferring the string energy don't deform either material, the same amount of energy can be transferred regardless of surface area. But...
4. Attenuation from the surface area of the contact patch due to material properties. It's possible that a quite large contact area with quite low per-unit loading will suffer from a greater ratio of energy loss than a small contact area with a high per-unit load with actual lacquered wood, which is a fairly soft and dampening material. In other words, the smaller area could be more efficient after transfer loss is taken into account. I'm thinking big soft rubber ball and small steel ball bearing, both dropped onto a steel plate. The ball bearing rebounds almost perfectly, while the soft rubber ball absorbs a lot of the energy into itself.
5. I know violins are different, but they have quite tiny feet on their bridges, the actual transfer path from the upper section of the bridge is very narrow, and they have quite thin extensions to spread the mechanical pre-load out a bit over the top so they don't dent it. The transfer area for the string energy is quite tiny.
To take this to bridge design, I think the surface area has more to do with not permanently denting the top after years of 35 pounds of downforce, but the actual sonic performance of the bridge has little to do with that, and may even be diminished. Tediously shaping the feet of the bridge to perfectly mate with the top is artistically valid, but doesn't affect the sound. In an adjustable bridge with the thumb-wheels, the surface area of the transfer point between the bridge base and the topper is (I had to work it out twice, I didn't believe it) 25 thousandths of a square inch (the area of the ends of the two threaded rods that get stuck into the bridge base). I believe that as long as the contact area between the bridge and the top is sufficient, more isn't better. What is "sufficient" I don't have a clue. My bridges tend to have a contact area of around 1.5 square inches between two feet, the feet landing over braces inside the guitar. And I do tediously shape the feet to mate perfectly with the top - a sign of good crafting, in my opinion...
Brian